init
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from numpy import arange, newaxis, hstack, prod, array
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from scipy import linalg
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def _central_diff_weights(Np, ndiv=1):
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"""
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Return weights for an Np-point central derivative.
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Assumes equally-spaced function points.
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If weights are in the vector w, then
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derivative is w[0] * f(x-ho*dx) + ... + w[-1] * f(x+h0*dx)
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Parameters
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----------
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Np : int
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Number of points for the central derivative.
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ndiv : int, optional
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Number of divisions. Default is 1.
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Returns
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-------
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w : ndarray
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Weights for an Np-point central derivative. Its size is `Np`.
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Notes
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-----
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Can be inaccurate for a large number of points.
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Examples
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--------
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We can calculate a derivative value of a function.
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>>> def f(x):
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... return 2 * x**2 + 3
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>>> x = 3.0 # derivative point
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>>> h = 0.1 # differential step
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>>> Np = 3 # point number for central derivative
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>>> weights = _central_diff_weights(Np) # weights for first derivative
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>>> vals = [f(x + (i - Np/2) * h) for i in range(Np)]
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>>> sum(w * v for (w, v) in zip(weights, vals))/h
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11.79999999999998
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This value is close to the analytical solution:
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f'(x) = 4x, so f'(3) = 12
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References
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----------
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.. [1] https://en.wikipedia.org/wiki/Finite_difference
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"""
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if Np < ndiv + 1:
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raise ValueError(
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"Number of points must be at least the derivative order + 1."
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)
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if Np % 2 == 0:
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raise ValueError("The number of points must be odd.")
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ho = Np >> 1
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x = arange(-ho, ho + 1.0)
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x = x[:, newaxis]
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X = x**0.0
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for k in range(1, Np):
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X = hstack([X, x**k])
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w = prod(arange(1, ndiv + 1), axis=0) * linalg.inv(X)[ndiv]
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return w
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def _derivative(func, x0, dx=1.0, n=1, args=(), order=3):
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"""
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Find the nth derivative of a function at a point.
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Given a function, use a central difference formula with spacing `dx` to
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compute the nth derivative at `x0`.
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Parameters
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----------
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func : function
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Input function.
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x0 : float
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The point at which the nth derivative is found.
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dx : float, optional
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Spacing.
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n : int, optional
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Order of the derivative. Default is 1.
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args : tuple, optional
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Arguments
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order : int, optional
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Number of points to use, must be odd.
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Notes
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-----
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Decreasing the step size too small can result in round-off error.
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Examples
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--------
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>>> def f(x):
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... return x**3 + x**2
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>>> _derivative(f, 1.0, dx=1e-6)
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4.9999999999217337
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"""
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if order < n + 1:
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raise ValueError(
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"'order' (the number of points used to compute the derivative), "
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"must be at least the derivative order 'n' + 1."
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)
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if order % 2 == 0:
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raise ValueError(
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"'order' (the number of points used to compute the derivative) "
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"must be odd."
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)
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# pre-computed for n=1 and 2 and low-order for speed.
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if n == 1:
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if order == 3:
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weights = array([-1, 0, 1]) / 2.0
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elif order == 5:
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weights = array([1, -8, 0, 8, -1]) / 12.0
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elif order == 7:
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weights = array([-1, 9, -45, 0, 45, -9, 1]) / 60.0
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elif order == 9:
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weights = array([3, -32, 168, -672, 0, 672, -168, 32, -3]) / 840.0
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else:
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weights = _central_diff_weights(order, 1)
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elif n == 2:
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if order == 3:
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weights = array([1, -2.0, 1])
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elif order == 5:
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weights = array([-1, 16, -30, 16, -1]) / 12.0
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elif order == 7:
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weights = array([2, -27, 270, -490, 270, -27, 2]) / 180.0
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elif order == 9:
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weights = (
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array([-9, 128, -1008, 8064, -14350, 8064, -1008, 128, -9])
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/ 5040.0
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)
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else:
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weights = _central_diff_weights(order, 2)
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else:
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weights = _central_diff_weights(order, n)
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val = 0.0
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ho = order >> 1
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for k in range(order):
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val += weights[k] * func(x0 + (k - ho) * dx, *args)
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return val / prod((dx,) * n, axis=0)
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